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Old 11-05-2008, 06:50 PM   #1 (permalink)
dappleyard
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Default can u help me with my math problems

i was hoping someone could give me the answers to theses questions and also explain how to do them....


i got to find x and y but also get x and y as same numbers for both parts of the question

1.
8x-3y=8
5x -3y=5

2.
4x + 5y = 17
2x - 5y = 1

3.
7x + 2y = 8
6x - 2y =5

2.




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Old 11-05-2008, 07:03 PM   #2 (permalink)
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please really need help



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Old 11-05-2008, 07:05 PM   #3 (permalink)
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Quote:
Originally Posted by dappleyard View Post
i was hoping someone could give me the answers to theses questions and also explain how to do them....


i got to find x and y but also get x and y as same numbers for both parts of the question

1.
8x-3y=8
5x -3y=5

2.
4x + 5y = 17
2x - 5y = 1

3.
7x + 2y = 8
6x - 2y =5

2.
Ah, good old simultaneous equations. Well I won't do them all for you, I'll try my best to explain.

You first need to cancel out one of the terms. With these, it is easy, because the y terms are the same eg. in 1) they are both 3y. To cancel the 3y's out you need to minus one equation from the other.

So for the first example, taking one from the other, we get 3x = 3, or -3x = -3 (depending on which equation you subtract)

This will give x as 1. You can then bung x = 1 into either of the two equations. This will give 8 - 3y = 8 or 5 - 3y = 5. So y = 0. Then take your values of x and y and put them into the other equation to check that you are right.



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Old 11-05-2008, 07:06 PM   #4 (permalink)
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If x and y have to be the same number then you should replace y with x.And the solve it.

I think ? Ah **** it I don't understand it.I got vacation!

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Old 11-05-2008, 07:07 PM   #5 (permalink)
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Its pretty easy. You have to get a variable by itself on one side of the equation. That's a good start. Its pretty easy after that. I would imagine you probably learned that pretty recently.




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Old 11-05-2008, 07:08 PM   #6 (permalink)
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Yea, Bond explained it a little better.

Algebra. I used to be good at it. Its been a while.




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Old 11-05-2008, 07:13 PM   #7 (permalink)
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I'm not that great at explaining stuff. I can understand Maths really well, but when it comes to describing to someone else, I find it really hard. Hopefully that explanation has been of some use to you.



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Old 11-05-2008, 07:16 PM   #8 (permalink)
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Ahhh, yeah, basically just add together the equations one part a time.
So add your X terms, your Y terms, and your Term on the other side of the equal sign.
P.S. How old are you, because funny thing is I just learned about this stuff in this Quarter of algebra.

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Old 11-05-2008, 07:19 PM   #9 (permalink)
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to be honest i still dont get this at all



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Old 11-05-2008, 07:21 PM   #10 (permalink)
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These are the easiest kind!

All you have to do is subtract/add the equations.

In the harder ones, you have to make them the same before you can do that


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